Answer: 82
Step-by-step explanation:
The formula to find the sample size is given by :-
, where E = Margin of error.
= Population standard deviation for the prior study.
As per given , we have
gallons.
Margin of error : E= 110 gallons
Critical value for 99% confidence level = z* = 2.576
Then, the required sample size : 
{Rounded to the nearest integer.}
Hence, the minimum sample size = 82
Answer:
Step-by-step explanation:
Answer:
closest option B (50.24)
Step-by-step explanation:
A=πr²
= π×4×4
=π×16
=50.265m²
The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ = <u> σ/√n </u>.
In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.
We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.
The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.
Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ= <u> σ/√n </u>.
Learn more about sampling distribution at
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The provided question is incomplete. The complete question is:
"Fill in the blanks to correctly complete the sentence below.
Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.
The sampling distribution of x has mean μₓ =______ and standard deviation σₓ =______."
