What are the solutions of the equation: z^2 - 12z + 36 = 0?

1 answer:

Helen [10]3 years ago

5 0

Factor by groups
(Z^2 -6z) (-6z+36)
GCF 1st binomial is z
GCF of 2nd binomial is -6
(z-6)(z-6)
Solutions
6,6

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