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boyakko [2]
3 years ago
10

5log625+25log625+625log625

Mathematics
1 answer:
inysia [295]3 years ago
7 0
loc_c(a^m)=mlog_ca \\log_ca+log_cb=log_c(a \times b)  \\ a^x \times a^y=a^{x+y}\\   \\ 5^2=25 \\ 5^4=625 \\  \\ 5log625+25log625+625log625= \\ log(625^5)+log(625^{25})+log(625^{625})= \\ log(5^{4 \times 5}) + log(5^{4 \times 25}) + log(5^{4 \times 625}) = \\ log5^{20}+log5^{100}+log5^{2500}= \\ log(5^{20}\times5 ^{100} \times 5^{2500})= \\ log5^{20+100+2500}= \\ log5^{2620}= \\ 2620log5
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Which of the following must describe an irrational number
zubka84 [21]

Answer:

An Irrational number is a number that cannot be expressed as the ratio of two integers.

Example: \pi

its numbers are infinite

6 0
3 years ago
Zachery is solving the equation 3/4 (x - 8) = 12
Maru [420]

Answer:

3/4*x - 3/4*8=12

3/4x -6=12

3/4x=12+6

3/4x=18

x=24

Step-by-step explanation:

multiply 3/4 into the content inside the brackets

have -3/4*8 cross the equal sign changing its sign from - to +

divide both sides by 3/4

6 0
3 years ago
At a restaurant, three salads, two sandwiches, and one drink cost $17.75. One salad, one sandwich, and three drinks cost $10.75.
Leno4ka [110]

Answer:

A salad costs $2.50

A sandwich costs $4.50

A drink costs $1.25

Step-by-step explanation:

Let x represent the salad, y represent the sandwich, and z represent the drink.

Since three salads, two sandwiches, and one drink cost $17.75:

3x + 2y + z = 17.75  (1)

Since one salad, one sandwich, and three drinks cost $10.75:

x + y + 3z = 10.75  (2)

Since a salad costs twice as much as a drink:

x = 2z  (3)

Multiply the equation 2 by -2 then, sum the equation 1 and equation 2:

-2x - 2y - 6z = -21.50

3x + 2y + z = 17.75

→ x - 5z = -3.75

Replace the x with 2z using equation 3:

2z - 5z = -3.75

-3z = -3.75

z = 1.25

x = 2z → x = 2.50

x + y + 3z = 10.75 → 2.50 + y + 3.75 = 10.75 → y + 6.25 = 10.75 → y = 4.50

5 0
3 years ago
Expanded form for 2,937,082
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3 years ago
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Inequality: a checking-account balance is no more than $500
matrenka [14]

x≤ 7 is the answer I could find hope it helps

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3 years ago
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