Answer:
Both length and width of 7.25m
Step-by-step explanation:
Let L and W be the length and width of the rectangle, respectively. Since the perimeter is 29, we have the following equation
(L + W)2 = 29
L + W = 29/2 = 14.5
L = 14.5 - W
Also the area of the rectangle would be as the following:
A = LW = W(14.5 - W) = 14.5W - W^2
To find the maximum area possible, we can take the first derivative and set it to 0
A' = 14.5 - 2W = 0
2W = 14.5
W = 14.5 / 2 = 7.25m
L = 14.5 - W = 14.5 - 7.25 = 7.25m
