The answer to this question is b
B.) Hibiscus Street
The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept
So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.
Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
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A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.
C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.
D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.
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You can download the app photo math and that will help you
450/30
15
15/3x =5
x= 5
5+2y= 315
5-5+2y =315-5
2y = 310
2y/2 = 310/2
y=155
Step-by-step explanation:
450/45
10
2x+4y=450
2×5=10
10+(4×155)
=620/155
=4
10/5=2
Answer:
12x^2+2x+7
Step-by-step explanation:
Distribute the Negative Sign:
=4x^2+6+7+−1(−8x^2−2x+6)
=4x^2+6+7+−1(−8x^2)+−1(−2x)+(−1)(6)
=4x^2+6+7+8x^2+2x+−6
Combine Like Terms:
=4x^2+6+7+8x^2+2x+−6
=(4x^2+8x^2)+(2x)+(6+7+−6)
=12x^2+2x+7
