3 years ago

7. Name three non-collinear points? JNL JKL оооо KNR LKJ

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Answer:

JNL,JKL,KNR are three non-collinear points

You might be interested in

What is the missing addend?<br> 52,835 +<br> = 87,216

posledela

Answer: 34,381

Step-by-step explanation:

You have to subtract 52,835 by the sum 87,216 which will get you the answer of 34,381

6 0

3 years ago

Read 2 more answers

Distance= 2797.2 time= 0.15 speed

Nutka1998 [239]

Speed = Distance ÷ Time

Distance = 2797.2

Time = 0.15

2797.2 / 0.15 = 18,648

Speed = 18,648

7 0

3 years ago

Read 2 more answers

2. Find the surface area of the solid

PolarNik [594]

Answer:

C. SA = 148.8 ft

Step-by-step explanation:

3.1×8×6= 148.8

4 0

3 years ago

A professor records the difference between the marks scored by the students in the class test last week and those scored in the

dezoksy [38]

Answer: $(10.82\ , 13.18)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\mu\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 35 , large sample (n>30)

Mean difference : $\overline{x}=12$

Standard deviation : $\sigma=3$

Significance level : $\alpha=- 1-0.999=0.001$

Critical value : $z_{\alpha/2}=z_{0.0005}=3.4807567$

Now, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students will be :-

$12\pm\ (3.4807567)\dfrac{2}{\sqrt{35}}\\\\=12\pm1.18\\\\=(10.82\ , 13.18)$

Hence, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students = $(10.82\ , 13.18)$

4 0

3 years ago

Angela works a basic week of 40 hours and her hourly rate of pay is $12.50. Calculate her weekly wage.

lutik1710 [3]

Answer:

$500

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers