x and y are the packs of organic and inorganic fertilizer, respectively.
pounds of nitrogen added = 2x + 6y = 120
pounds of potassium added = 3x + 2y = 54
eliminate the y terms. subtract the first equation from 3 times the second equation.
9x + 6y = 162
-2x - 6y = -120
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7x = 42
x = 6
y = 18
Well first you have to solve for the 1st year so 200*.03, .03 represents the 3%. Which would equal 6 dollars so after the 1st year he would have 200+6=206.
Now you do the second year so do 206*.03, which would equal 6.18 so 206+6.18=212.18
Answer= 212.18
6d - 8f + 2
hope this helps
