Answer:
that would mean 15$ a year
1.25$ a month
Step-by-step explanation:
hope it helped
This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.
let the two numbers be x and y.
Multiply to 44. x*y = 44 ..........(a)
Add up to 12. x + y = 12 .........(b)
From (b)
y = 12 - x .......(c)
Substitute (c) into (a)
x*y = 44
x*(12 - x) = 44
12x - x² = 44
-x² + 12x = 44
-x² + 12x - 44 = 0.
Multiply both sides by -1
-1(-x² + 12x - 44) = -1*0
x² - 12x + 44 = 0.
This does not look factorizable, so let us just use quadratic formula
comparing to ax² + bx + c = 0, x² - 12x + 44 = 0, a = 1, b = -12, c = 44
x = (-b + √(b² - 4ac)) /2a or (-b - √(b² - 4ac)) /2a
x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)
x = (12 + √(144 - 176) )/ 2
x = (12 + √-32 )/ 2
√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2
Where i is a complex number. Note the equation has two values. We shall include the second, that has negative sign before the square root.
x = (12 + √-32 )/ 2 or (12 - √-32 )/ 2
x = (12 + 4i√2 )/ 2 (12 - 4i√2 )/ 2
x = 12/2 + (4i√2)/2 12/2 - (4i√2)/2
x = 6 + 2i√2 or 6 - 2i√2
Recall equation (c):
y = 12 - x, When x = 6 + 2i√2, y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2
When x = 6 - 2i√2, y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2
x = 6 + 2i√2, y = 6 - 2i√2
x = 6 - 2i√2, y = 6 + 2i√2
Therefore the two numbers that multiply to 44 and add up to 12 are:
6 + 2i√2 and 6 - 2i√2
Answer:
5
Step-by-step explanation:
When you divide 25/5 the answer is 5 dollars per store
Answer:
a 4 1/5
b 7 7/24
Step-by-step explanation:
a 7/9 * 5 2/5
Change the mixed number to an improper fraction
7/9 * (5*5+2)/5
7/9 * 27/5
Rewrite
7/5 * 27/9
7/5 * 3
21/5
Change this back to a mixed number
5 goes into 21 4 times (4*5 = 20 ) with 1 left over
4 1/5
b 1 3/4 * 4 1/6
Change to improper fractions
(4*1+3)/4 * (6*4+1)/6
7/4 * 25/6
175/24
Change back to a mixed number
24 goes into 175 7 times (7*24 =168 ) with 7 left over
7 7/24
Answer:
1 / x^8
Step-by-step explanation:
We know that a^b / a^c = a^ (b-c)
x^7 / x^ 15 = x^ (7-15) = x^-8
We also that that a^-b = 1/ a^b
x^-8 = 1 / x^8
