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2 years ago

12

Find the domain of the graphed function. Help me please);

1 answer:

pogonyaev2 years ago

8 0

The correct answer is B. -4<x<2.

This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.

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Find the area of the parallelogram with vertices a(1,2,3), b(1,3,6), c(3,8,6), and d(3,7,3,)

Julli [10]

The answer is: <span>A=<span>√265</span></span>.

4 0

3 years ago

The temperature function (in degrees Fahrenheit) in a three dimensional space is given by T(x, y, z) = 3x + 6y - 6z + 1. A bee i

madam [21]

You're looking for the extreme values of $T(x,y,z)=3x+6y-6z+1$ subject to $x^2+y^2+z^2=9$ . The Lagrangian is

$L(x,y,z,\lambda)=3x+6y-6z+1+\lambda(x^2+y^2+z^2-9)$

with critical wherever the partial derivatives vanish:

$L_x=3+2\lambda x=0\implies x=-\dfrac3{2\lambda}$

$L_y=6+2\lambda y=0\implies y=-\dfrac3\lambda$

$L_z=-6+2\lambda z=0\implies z=\dfrac3\lambda$

$L_\lambda=x^2+y^2+z^2-9=0$

Substituting the first three solutions into the last equation gives

$\dfrac9{4\lambda^2}+\dfrac9{\lambda^2}+\dfrac9{\lambda^2}=9$

$\implies\lambda=\pm\dfrac32$

$\implies x=1,y=2,z=-2\text{ or }x=-1,y=-2,z=2$

At these points, we have

$T(1,2,-2)=28$

$T(-1,-2,2)=-26$

so the highest temperature the bee can experience is 28º F at the point (1, 2, -2), and the lowest is -26º F at the point (-1, -2, 2).

6 0

3 years ago

I need to know how to do this math problem

ladessa [460]

figure it out yourself

5 0

3 years ago

Hey can some one help me out

Archy [21]

I believe the correct situation is C

3 0

2 years ago

The tree in Charlie’s backyard is 9 meters high. how high is it in centimeters

butalik [34]

If you use metric conversion (shown below), you will find that 9 meters = 90 cm. Tell me if you need further explanation.

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2 years ago