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puteri [66]
3 years ago
9

Complete the proof proving YUZ~VWZ

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

1. ΔXYZ is a right Δ with altitude YU.

Given

2. ΔXYZ ~ ΔYUZ

Right Triangle Altitude Similarity Theorem

3. VW || XY

Given

4. ∠VWZ ≅ ∠XYZ

Corresponding angles

5. ∠Z ≅ ∠Z

Reflexive property of congruence

6. ΔXYZ ~ ΔVWZ

AA Similarity postulate

7. ΔYUZ ~ ΔVWZ

Transitive property of similar triangles

Step-by-step explanation:

The first statement is given in the problem.  Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.

Next, we are given in the problem statement that the lines VW and XY are parallel.  Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent.  And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.

Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.

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just olya [345]

Answer:

-2.7 < y

Step-by-step explanation:

2.9 < 5.6+y

Subtract 5.6 from each side

2.9-5.6 < 5.6-5.6+y

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4 0
3 years ago
Is the expression 5 (3m+2p) -4m equivalent to the expression 13p+11m-3p?
Aleksandr [31]
 5 (3m+2p) -4m= 15m +10p -4m
=11m +10p
--------------------------------------------------------
13p+11m-3p=10p -11m
-----------------------------------------------------------
Yes, 5 (3m+2p) -4m is  equivalent to the expression 13p+11m-3p as i worked out for you.. Hope this helps you!!! =')

7 0
3 years ago
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12345 [234]

Hello there! :)

Answer:

\boxed{b>8}\checkmark

<h2><u><em>*****The answer should have a GREATER THAN SIGN AND POSITIVE TOO!*****</em></u></h2>

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

PEMDAS

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Parenthesis

Exponent

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Divide

Add

Subtract

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First, you add by 4 from both sides of an equation.

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Then, you add numbers from left/right.

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\boxed{b>8}, which is our final answer.

Hope this helps you!

Have a nice day! :)

:D

-Charlie

Thank you so much! :)

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D is the correct answer.

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Find the portion of the graph that is above the x-axis.

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3 years ago
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