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3 years ago

Solve the system using elimination

1 answer:

6 0

Eliminate x's
multiply 2nd equation by -2 ad add to first

2x+3y=9
-2x-10y=-16 +
0x-7y=-7

-7y=-7
divide by -7
y=1

sub back

2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3

x=3
y=1

(x,y)
(3,1)

D

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Answer:

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Step-by-step explanation:

To convert 1.68 to a percentage, multiply the number 1.68 by 100.

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Answer:

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n = 12

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P = principal amount = $300

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Yearly compounding interest rate

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3 years ago

Subtract. Use models if needed. (12x + 3) – (2x + 10)

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A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

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Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

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Answer:

56 degrees

Step-by-step explanation:

We know that the angle TWR must be 90 degrees because TWK is 90 degrees and the two angles msut add up to 180. Since we know that TWR=90 degrees and since LWR=34 degrees we do 90-34 so angle 2=56 degrees.

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