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arsen [322]
3 years ago
15

Solve the system using elimination

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0
Eliminate x's
multiply 2nd equation by -2 ad add to first

2x+3y=9
<u>-2x-10y=-16 +</u>
0x-7y=-7

-7y=-7
divide by -7
y=1

sub back

2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3


x=3
y=1

(x,y)
(3,1)

D
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"solve each system by graphing"
garik1379 [7]
Put them into y=mx+b
y=1/3x -1 
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
3 0
3 years ago
What is the greatest possible product of a 2 digit number and a 1 digit number?? explain how u know
KIM [24]
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Hope this helps! :)
4 0
3 years ago
The function f(x) is graphed on the coordinate plane.
soldier1979 [14.2K]

Answer:

f(-4) = 4

Step-by-step explanation:

Fro the graph attached,

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5 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
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2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
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Angelina_Jolie [31]
Use Photomath or desmo to give you the answer
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