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arsen [322]
3 years ago
15

Solve the system using elimination

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0
Eliminate x's
multiply 2nd equation by -2 ad add to first

2x+3y=9
<u>-2x-10y=-16 +</u>
0x-7y=-7

-7y=-7
divide by -7
y=1

sub back

2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3


x=3
y=1

(x,y)
(3,1)

D
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Write 1.68 as a percent.
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Answer:

1.68 as a percent is 168%.

Step-by-step explanation:

To convert 1.68 to a percentage, multiply the number 1.68 by 100.

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Answer:

P = $300

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n = 12

$544.61  (to the nearest cent)

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Step-by-step explanation:

P = principal amount = $300

r = annual interest rate in decimal form = 15% = 15/100 = 0.15

n = number of times interest is compounded per unit t = 12

<u>How much she'll owe in 4 years</u>

P = 300

r = 0.15

n = 12

t = 4

P(1+\frac{r}{n})^{nt}=300(1+\frac{0.15}{12})^{12 \times 4}

= $544.61  (to the nearest cent)

<u>Yearly compounding interest rate</u>

P(1+r)^t

<u>How much she'll owe in 4 years at yearly compounding interest</u>

P(1+r)^t=300(1+0.15)^4

= $524.70  (to the nearest cent)

7 0
2 years ago
Subtract. Use models if needed.<br><br><br> (12x + 3) – (2x + 10)
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A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

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Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

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3 years ago
Question: What is the measure of angle 2?
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