10 x 90.3 = 903
10 x 90.6 = 906
The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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Answer:
C
Step-by-step explanation:
If Ricardo started studying at 4 p.m and for sure will not stop until after 7 p.m, that means that he will be studying for 3 hours at least, and maybe even longer. So the time he will spend studying is at least 3 hours.
Therefore, x>3, where x is the time Ricardo will spend studying.
It doesn't have to be called width
So just use the formula.
A=h×w
A=2×8.5
A=17
The area of the rectangle is 17 meters
Since you are recycling the boxes you will be subtracting 2 3/6 and 1 2/3 since you’re a denominators you’re not mad she have to find a common denominator which would be six. So you have to do 2/2 x 2/3 = 4/6. So then you would do 3/6 - 4/6 = 1/6. Then you would subtract 1-2=1. Then you would do 1 + 1/6 = 1 1/6
So the answer is 1 1/6.
I hope this helped
