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LenKa [72]
3 years ago
7

What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24

Mathematics
2 answers:
german3 years ago
5 0
\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}

=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}
Tcecarenko [31]3 years ago
3 0

The answer is \frac{(x+3)(x-5)}{x-4} , x\neq-6, x\neq-2,  x\neq4

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