The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times.

When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 63 seconds and a standard devia

Gnom [1K]

Answer: in 95% of races, his finishing time will be between 62 and 64 seconds.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 63 seconds and the standard deviation is 5 seconds.

2 standard deviations = 2 × 0.5 = 1

63 - 1 = 62 seconds

63 + 1 = 64 seconds

Therefore, in 95% of races, his finishing time will be between 62 and 64 seconds.

6 0

3 years ago

Which of the four is it?

Anna11 [10]

Answer:

option 1 i believe

Step-by-step explanation:

just worked it out

i hope this is right and helps <3

6 0

3 years ago

Edger Anderson earns $300 A week plus a 15 percent commission only on sales he makes after his first $1000 In sales.if Mr.Anders

Mama L [17]

525 is what i got as my answer good luck

4 0

3 years ago

Read 2 more answers

Find the critical value of x2 based on the given information H1 >3.5 n=14 a=0.05

egoroff_w [7]

Answer:

The degrees of freedom are given by:

$df = n-1=14-1=13$

The significance level is $\alpha=0.05$ and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

$\chi^2_{\alpha}= 22.362$

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: $\sigma^2 \leq 3.5$

Alternative hypothesis: $\sigma^2 >3.5$

The degrees of freedom are given by:

$df = n-1=14-1=13$

The significance level is $\alpha=0.05$ and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

$\chi^2_{\alpha}= 22.362$

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0

3 years ago

Imagine a deck of 500 cards numbered from 1 to 500. If all the cards are shuffled randomly and you are asked to pick three cards

amm1812

Answer:

P = 1 / 6

Step-by-step explanation:

Given:-

- A deck has 500 cards

- Numbered from 1-500

Find:-

you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card

Solution:-

- Suppose we draw three cards. We don't care what they actually are, irrespective of number.

- Let the three numbers be a, b, c: Such that:

a < b < c.

- The total possible combinations with 3 numbered cards will be:

a b c

b a c

a c b

b a c

b c a

c a b

- We have 6 possibilities for 3 numbered cards. So the probability of of each subsequent card being larger than the previous drawn card would be:

P = 1 / possible combinations

P = 1 / 6

6 0

3 years ago