Answer: Law of conservation of energy
Heat Loss by the metal = Heat Gain by the water (Assume no heat loss to the environment)
M₁C₁ΔT₁= M₂C₂ΔT₂
Where
C₁ and C₂ = the specific heat capacities of the metal and water = C₁?, 4.182J/gK
ΔT₁ and ΔT₂ = Temperature changes of the metal and the water
ΔT₁ = (373 - 300.8)K and ΔT₂= (300.8 - 296.7)K convert to S.I units
M₁ and M₂ are the masses of the metal and water = 59.047g, but
M₂ = density x volume = 1kg/m³ x 0.1m³=0.1kg
Note: Volume of water = 100ml=0.1m³, also density of water = 1kg/m³
We have,
0.059kg x C₁J/KgK (373 - 300.8)K = 0.1kg x 4182J/kgK (300.8 - 296.7)K
4.259C₁=1715J/KgK
C₁=402.5J/KgK
The specific heat of the metal is 402.5J/KgK
Answer:
4
Explanation:
You assume that when they were writing two zeroes after the decimal point, they wanted to show that these are significant in determining the precision of this number.
Answer:Transformer
Explanation:All the other devices generate their own electricity apart from power line and Transformer, power line just carries electricity. A transformer can be used to step up or step down voltages from a source.