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likoan [24]
3 years ago
9

which of these changes does a submarine encounter as it returns from the bottom of the ocean to the surface of the ocean? a. the

amount of sunlight increases. b. the water temperature decreases. c. the amount of plants decreases. d. the water pressure increases.
Physics
2 answers:
andrey2020 [161]3 years ago
6 0

Answer

Correct option is a ( the amount of sunlight increases)

Explanation:

a. Sunlight does not penetrate the deep ocean it means at the bottom of ocean there is complete darkness. So when a submarine returns from the bottom of the ocean to the surface the amount of sunlight increases.

b.Usually temperature decreases with depth of ocean so this option is not correct.

c.This is also not correct option because on the surface of the ocean there may be island on which there may be lots of plants.

d. Pressure decreases on moving upward direction so this option is also not correct

Lady bird [3.3K]3 years ago
4 0
The amount of sunlight increases 
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A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo
Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

W = \Delta U = U_2 - U_1

where the potential energy is defined as follows

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Let's first calculate the distance 'r' for both positions.

r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m

Now, we can calculate the potential energies for both positions.

U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J

Finally, the total work done on the moving particle can be calculated.

W = U_2 - U_1 = (-0.829) - (-3.57) = 2.74~J

4 0
3 years ago
Read 2 more answers
Starting at its rightmost position, it takes 2 seconds for the pendulum of a grandfather clock to swing a horizontal distance of
sdas [7]

Answer:

The correct answer is b,  x = 9 cos (pi / 2 t)

Explanation:

The equation that describes a simple pendulum is

             θ  = θ₀  cos (wt + φ)

The angle is measured is radians

            θ = x / L

We replace

           d / L = x₀ / L cos (wt + φ)

            x₀ = 9 in

         

We replace

             d = 9 cos (wt + φ)

Angular velocity is related to frequency and period.

           w = 2π f = 2π / T

The period is the time of a complete oscillation T = 4 s

           w =2π / 4

           w = π / 2

Let's replace

             x = 9 cos (π/2 t + φ)

As the system is released from the root x = x₀ for t = 0 s

              x₀ = x₀ cos φ

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The final equation is

             x = 9 cos (pi / 2 t)

The correct answer is b

8 0
3 years ago
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What is your worldview? Explain?
zimovet [89]

My worldview is someone who doesn't exist. Someone who isn't real but i want them to BE real. It's not possible to have someone who is alike you. Who is there for yo when you need them

5 0
2 years ago
What are the Rules of magnetism
Keith_Richards [23]

all the allials must be aligned in the same direction

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Write answers with significant figures:<br>a) 17.35 g +8.498 g​
Genrish500 [490]

Answer:

25.9 g

Explanation:

= 17.35

8.498

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= 25.848 g = 25.85 g = 25.9 g

*so sorry if wrong

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