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3 years ago

Which occurs at a transform boundary?

1 answer:

5 0

The answer is B. One plate slides past another.

The San Andreas Fault in California and the Alpine Fault in New Zealand are examples of transform boundaries.

Hope this helps! :)

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Convert 592 minutes to seconds. using one step conversion.

vovangra [49]

Answer:

35520

Explanation:

592 times 60=35520

8 0

3 years ago

joe spend 8 on lunch and 6.50 on dry cleaning . He also buys 2 shirts that each cost the same smount. joe spend a total of $52 w

Gnesinka [82]

8+6.5+2x=52
52/2=8+6.5+x
26=8+6.5+x
26-8-6.5=x
11.5=x

6 0

4 years ago

Using pressure and density of fluids.

mario62 [17]

snow shoes.

shoes with large areas in contact with the snoow. reduces the pressure on the snow, and alows you to sink less. or to walk on the surface.

Stilettp high heels would have the opposite effect

7 0

3 years ago

The half-life of radium-224 is approximately 3.66 days. Step 1 of 3 : Determine a so that A(t)=A0at describes the amount of radi

Dafna11 [192]

Answer:

a = 0.827468

Explanation:

given,

half life of radium-224 = 3.66 days

now,

$A(t) = A_0 a^t$

t is the time

A₀ is the amount at t = 0

at t = 0 , A(0) = 1

A(3.66) = 1/2

at t = 3.66

$A(t) = A_0 a^t$

$\dfrac{1}{2}= 1. a^{3.66}$

taking log both side

3.66 log (a) = log (0.5)

log a = -0.0822

now, $a = 10^{-0.0822}$

a = 0.827468

4 0

3 years ago

The coil springs on a car's suspension have a value of k = 64000 N/m. When the

AlladinOne [14]

80 joule is momentarily stored in each spring

Solution:

Given that,

The coil springs on a car's suspension have a value of k = 64000 N/m

When the car strikes a bump the springs briefly compress by 5.0 cm (.05 m)

By compressing the spring, we apply a force over a distance

As a result we have done work on the spring

Doing work means that we have transferred energy to spring in form of elastic potential

Therefore,

k = 64000 N/m

x = 0.05m

The elastic potential energy is given as:

$PE = \frac{1}{2}kx^2$

Where, "k" is the spring constant and "x" is the displacement

$PE = \frac{1}{2} \times 64000 \times 0.05^2\\\\PE = 32000 \times 0.0025\\\\PE = 80$

Thus 80 joule is momentarily stored in each spring

8 0

3 years ago