Find length CD first, which is the hypotenuse of the triangle.
PD = opposite
Opposite & hypotenuse = SOH or sin
Sin(27) = 15/H
x h, then ÷ sin(27)
H = 15/sin(27)
H = 33.04....
Move to triangle CDR:
15 is length opposite the angle we're after.
So far, we've got the hypotenuse (which we just found to be 33.04....) & the opposite of our triangle
Hypotenuse & opposite = SOH
Sin(x) = 15/33.04... but, to find the angle we do inverse of sin
sin-1(15/33.04...) = x
x = 27
(33.04... means I used the full numbers displayed on my calculator)
Thus, RCD is 27 degrees
Hope this helps!
Answer:
Step-by-step explanation:
Let us begin with the AA Similarity definition. It states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
This means that we need:
- An angle of one triangle that is congruent to an angle of the other triangle.
- Another angle of one triangle that is congruent to another angle of the other triangle.
For this problem, it is unclear that there are more than one angles that are congruent to each other. We see that angle <DEF and <ABC are congruent, but the problem does not give any other angles. In another case, we must find one more to prove similarity by the AA similarity theorem.
Answer: 
Step-by-step explanation:
The exponential function h, represented in the table, can be written as 
From table, at x=0, h(x) =10
Put theses values in equation,, we get
Also, for x= 1 , h(x) = 4, so put these values and a=10 in the equation , we get
Put value of a and b in the equation ,
→ Required equation.
Answer:
2 2/3 is Simplest form
Step-by-step explanation:
Answer:
Value of 
is 8.
Step-by-step explanation:
Given function,
![f(x)=\big[\frac{x}{2}\big]](https://tex.z-dn.net/?f=f%28x%29%3D%5Cbig%5B%5Cfrac%7Bx%7D%7B2%7D%5Cbig%5D)
we have to find :
It is known that,
![[x]](https://tex.z-dn.net/?f=%5Bx%5D)
=the greatest integer <=x
Then,
![\implies x=f^{-1}(\big[\frac{x}{2}\big])](https://tex.z-dn.net/?f=%5Cimplies%20x%3Df%5E%7B-1%7D%28%5Cbig%5B%5Cfrac%7Bx%7D%7B2%7D%5Cbig%5D%29)
Taking x=8 we get,
![f^{-1}(\big[\frac{x}{2}\big])=x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28%5Cbig%5B%5Cfrac%7Bx%7D%7B2%7D%5Cbig%5D%29%3Dx)
![\implies f^{-1}(\big[\frac{8}{2}\big])=8](https://tex.z-dn.net/?f=%5Cimplies%20f%5E%7B-1%7D%28%5Cbig%5B%5Cfrac%7B8%7D%7B2%7D%5Cbig%5D%29%3D8)
![\implies f^{-1}([4])=8](https://tex.z-dn.net/?f=%5Cimplies%20f%5E%7B-1%7D%28%5B4%5D%29%3D8)
( Since [4]=4 )
Hence the value of is 8.
