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Debora [2.8K]
3 years ago
14

A 32.5 g cube of aluminum initially at 45.8 °C is submerged into 105.3 g of water at 15.4 °C. What is the final temperature of b

oth substances at thermal equilibrium? (Assume that the aluminum and the water are thermally isolated from everything else.)
Physics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

T = 17.26 ^oC

Explanation:

At thermal equilibrium we have heat given by aluminium must be equal to the heat absorbed by the water

so we will have

Q_1 = Q_2

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

so we will have

32.5(900)(45.8 - T) = 105.3(4186)(T - 15.4)

so we have

(45.8 - T) = 15.1(T - 15.4)

so we have

16.1 T = 277.87

T = 17.26 ^oC

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Answer:

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Explanation:

Given:

Mass of the block is, m=40\ kg

Height to which it is raised is, h=2\ m

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