Ask question

Ask question

All categories

2 years ago

12

How does alpha particles transfer energy to their surroundings?

1 answer:

Juli2301 [7.4K]2 years ago

4 0

Answer :

A Alpha Radiation. As charged particles, such as alpha particles, move through material, energy is transferred from the radiation to the atoms or molecules that make up the material. The major energy-loss mechanisms are electronic excitation and ionization.

Hope this helps :)

You might be interested in

What work is the person doing doing to the box if the box is just being held and it is not moving?

kobusy [5.1K]

Allowing for a platform in which the box holds potential energy

7 0

3 years ago

A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 37.6 m/s when the pilot receiv

IrinaVladis [17]

Answer:

7 m/s^2

Explanation:

Given that the jet is traveling 37.6 m/s when the pilot receives the message.

And it takes the pilot 5.37 s to bring the plane to a halt.

Acceleration of the plane can be calculated by using first equation of motion

V = U - at

Since the plane is going to stop, the final velocity V = zero.

And the acceleration will be negative

Substitute all the parameters into the formula

0 = 37.6 - 5.37a

5.37a = 37.6

Make a the subject of formula

a = 37.6 / 5.37

a = 7.0 m/s^2

Therefore, the acceleration of the plane to bring the plane to a halt is 7 m/s^2

5 0

3 years ago

If an astronaut weighs 900 n on earth, what does he weigh on the planet venus?

Ber [7]

Use w=m*g value of g is 1.67m/s^2

5 0

3 years ago

Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea

Kipish [7]

Answer:

6.5 m/s

Explanation:

We are given that

Distance, s=100 m

Initial speed, u=1.4 m/s

Acceleration, $a=0.20 m/s^2$

We have to find the final velocity at the end of the 100.0 m.

We know that

$v^2-u^2=2as$

Using the formula

$v^2-(1.4)^2=2\times 0.20\times 100$

$v^2-1.96=40$

$v^2=40+1.96$

$v^2=41.96$

$v=\sqrt{41.96}$

$v=6.5 m/s$

Hence, her final velocity at the end of the 100.0 m=6.5 m/s

5 0

3 years ago

On the Moon, the acceleration due to the effect of gravity is only about 1/6 of that on Earth. An astronaut whose weight on Eart

Ulleksa [173]

A = 94.22 Newtons

b = 58.16 kg

Gravity on the moon is 1.62 m/s^2

8 0

3 years ago