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2 years ago

With a 900 V source, voltage is divided across 3 series resistors of 300 V, 280 V, and:

Physics

1 answer:

telo118 [61]2 years ago

6 0

Answer:

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You are a guest magician in a circus. One of your tricks is to place a football on an inclined plane without the football rollin

kaheart [24]

Answer:

You are a guest magician in a circus. One of your tricks is to place a football on an inclined plane without the football rolling over is explained below in details.

Explanation:

spinning ball halts after traveling some range due to friction energy act different direction of movement of the ball. you can observe in the figure.

Let any rolling ball of mass (m ) is traveling with velocity v ,

common effect on ball (N) = mg

because of motion, friction energy develops on the contact exterior and begins to resist the movement of the rolling ball.

hence,

fr = uN = umg act on communicating exterior, so, after any time due to friction energy rolling ball gets to rest.

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2 years ago

The image shows one complete cycle of a mass on a spring in simple harmonic motion. An illustration of a mass on a vertical spri

Alja [10]

Answer:

D. "The net force is zero, so the acceleration is zero"

Explanation:

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3 years ago

Now instead a 3-mw laser of wavelength λ = 760 nm is directed into the interferometer (with the mirror m1 at the displacement ca

slavikrds [6]

power received will always remain same and does not depends on the distance

it will be same as the power of source

$P = 3 mW$

now the energy released by one photon is given as

$E = \frac{hc}{\lambda}$

$E = \frac{6.6* 10^{-34}* 3 * 10^8}{760 * 10^{-9}}$

$E = 2.6 * 10^{-19} J$

now let say N photons per second released

$N * 2.6 * 10^{-19} = 3 * 10^{-3}$

$N = 1.15* 10^{16} per\: second$

7 0

2 years ago

A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$