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arsen [322]
1 year ago
12

An installation consists of a 30-kVA, 3-phase transformer, a 480-volt primary, and a 240-volt secondary. Calculate the largest s

tandard size circuit breaker permitted for primary-only protection to be used without applying Note 1 of Table 450.3(B).
Physics
1 answer:
Nikitich [7]1 year ago
5 0

Answer:  45 A

Explanation:

Primary only protection 3-phase

I =  3 phase kVA / ( 1.723 * V)

I = 30000 / ( 1.732 * 480 ) = 36.085 A

Table 450.3(B)

Currents of 9A or more column

primary only protection  = 125%

Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A

 Table 450.3(B) Note 1   does not apply, use next smaller Table 240.6(A)

Next smaller = 45 A

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A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant
Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line  and police car catches motorist after s distance

Distance travel by motorist

s=v_mt----1

Distance traveled by Police car

s=ut+\frac{at^2}{2}

s=0+\frac{a_pt^2}{2}

s=\frac{a_pt^2}{2}----2

from 1 & 2 we get

t=\frac{2v_m}{a_p}

(a)Velocity of Police car after t sec

v=u+a_pt

v=0+a_p\times \frac{2v_m}{a_p}

v=2v_m

(b)time taken by police car is

t=\frac{2v_m}{a_p}

(c)Distance travel by police car=\frac{2v_m^2}{a_p}

7 0
3 years ago
What is the monthly cost of using a 750 W refrigerator that runs for 8 hours every day, if the cost per kWh is $0.23?
disa [49]

Answer:

Assuming there are 28 days in each month,

750W = 0.75kW

Cost of electric bill = 0.75 × 8 × 28 × $0.23

                               = $38.64

8 0
2 years ago
Find the momentum of a 25 kg remote
telo118 [61]

Answer:

100

Explanation:

Momentum (P) = Mass (M) × Velocity (V)

Momentum = 25kg × 4.0m/s

Momentum = 100kg m/s

7 0
3 years ago
what do you mean by momentum? avehicle is runing with a velocity of 5m/s. it the momentum of the vehicle is 5000kg m/s. what is
Fantom [35]
Momentum is simply a quantity that measures the impact of a moving body over something is due to the mass it posseses or the velocity with which it is moving. Mathematically,ut is the product of mass and velocity of a body. It is represented by capital p...(P) P=mv Solution to the problem: we know P=mv For mass,eliminate m from the equation, m=P/v Put values, m=5000/5=1000kg
8 0
3 years ago
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas
Pavel [41]

Complete question is:

A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 m/s. Neglect friction.

Answer:

(V_A) = 31.32 m/s

Explanation:

We are given;

car's mass, m = 1200 kg

h_A = 100 m

h_B = 150 m

v_B = 0 m/s

From law of conservation of energy,

the distance from point A to B is;

h = 150m - 100 m = 50 m

From Newton's equations of motion;

v² = u² + 2gh

Thus;

(V_B)² = (V_A)² + (-2gh)

(negative next to g because it's going against gravity)

Thus;

(V_B)² = (V_A)² - (2gh)

Plugging in the relevant values;

0² = (V_A)² - 2(9.81 × 50)

(V_A) = √981

(V_A) = 31.32 m/s

3 0
3 years ago
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