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3 years ago

What is the answer for 6k-9=-15

Mathematics

2 answers:

Svetach [21]3 years ago

8 0

6k -9 = -15
+9 +9
6k = 24
/6 /6
k = 4

docker41 [41]3 years ago

5 0

Simplifying 6k + -9 = -15 Reorder the terms: -9 + 6k = -15 Solving -9 + 6k = -15 Solving for variable 'k'. Move all terms containing k to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + 6k = -15 + 9 Combine like terms: -9 + 9 = 0 0 + 6k = -15 + 9 6k = -15 + 9 Combine like terms: -15 + 9 = -6 6k = -6 Divide each side by '6'. k = -1

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Step-by-step explanation:

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Step-by-step explanation:

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Question: An airport deli sells turkey, ham, and roast beef sandwiches. A customer can choose between turkey,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle \frac{1}{12}$ .

Step-by-step explanation:

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$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})\end{aligned}$ .

It is worth noting that this equality would not be valid if the choices are not independent. For example, if Ginger is more likely to choose mayonnaise after choosing cheese, then $P(\text{(roast beef) and (cheese) and (no mayonnaise)})$ and $P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})$ would likely be different.

What is the probabilities that Ginger would select roast beef for the sandwich? The question states that Ginger is "equally likely" to select each of turkey, ham, and roast beef. In other words:

$P(\text{roast beef})= P(\text{turkey}) = P(\text{ham})$ .

At the same time, Ginger has to choose exactly one of these options. She can't choose no meat of more than one options at a time. Therefore:

$P(\text{roast beef})+ P(\text{turkey}) + P(\text{ham}) = 1$ .

Combine these two equations to conclude that:

$\displaystyle P(\text{roast beef}) = \frac{1}{3}$ .

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$\displaystyle P(\text{cheese}) = \frac{1}{2}$ .
$\displaystyle P(\text{mayonnaise}) = \frac{1}{2}$ .

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$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise}) \\ &= \frac{1}{3} \times \frac{1}{2} \times \frac{1}{2} \\ &= \frac{1}{12}\end{aligned}$ .

8 0

4 years ago

Uring lunch hour at a local restaurant, 90% of the customers order a meat entrée and 10% order a vegetarian entrée. Of the custo

Furkat [3]

Answer:

Total percent of customers who order a drink with their entrée = 76%

Step-by-step explanation:

Let

Total customers = 100%

customers who order a meat entrée = 90%

customers who order a vegetarian entrée = 10%

Of the customers who order a meat entrée, 80% order a drink

% of customers who order a meat entrée and drink = 80% of 90%

= (80/100 * 90/100) * 100

= (0.8 * 0.9) * 100

= 0.72 * 100

= 72%

% of customers who order a meat entrée and drink = 72%

Of the customers who order a vegetarian entrée, 40% order a drink.

% of customers who order a vegetarian entrée and drink = 40% of 10%

= (40/100 * 10/100) * 100

= (0.4 * 0.1) * 100

= 0.04 * 100

= 4%

% of customers who order a vegetarian entrée and drink = 4%

What is the percent of customers who order a drink with their entrée?

Total percent of customers who order a drink with their entrée = % of customers who order a meat entrée and drink + % of customers who order a vegetarian entrée and drink

= 72% + 4%

= 76%

Total percent of customers who order a drink with their entrée = 76%

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3 years ago

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Ulleksa [173]

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3 years ago