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frosja888 [35]
2 years ago
8

20 POINTS!!!!!

Mathematics
1 answer:
inn [45]2 years ago
7 0

Answer:

D'accord. Ainsi, la flèche ou le pointeur doit pointer dessus. Si ne pointe pas, que. Découvrez-le

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???? please help lol
kow [346]

Answer:

  1. 150π ft²
  2. 10π ft.

Step-by-step explanation:

Area of the sector :

Area (sector) = \pi r^{2} \times \frac{\theta}{360^{o}}

Finding the area given r = 30 ft. and θ = 60° :

⇒ Area = π × (30)² × 60/360

⇒ Area = π × 900/6

⇒ Area = 150π ft²

===========================================================

Length of the arc :

Length (arc) =2 \pi r} \times \frac{\theta}{360^{o}}

Finding the arc length given r = 30 ft. and θ = 60° :

⇒ Arc Length = 2 × π × 30 × 60/360

⇒ Arc Length = 60/6 × π

⇒ Arc Length = 10π ft.

7 0
2 years ago
Read 2 more answers
Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5
timama [110]

f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3)  - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\

\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i

6 0
3 years ago
HELP! IS THIS PROPORTIONAL
MAXImum [283]

Answer:

Yes

Step-by-step explanation:

3 0
3 years ago
Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde
Lilit [14]

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

Point G is located at (6, 2)

When reflected over the y-axis:

G'(-6,2).

The ordered pair that best describes the location of G' is (-6,2).

5 0
2 years ago
Need help ASAP giving 25 points
Kruka [31]

Answer:

63in. 2

Step-by-step explanation:

7 0
3 years ago
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