Find the values of t6 and d for the arithmetic sequence with t6= 4 and t10= -4
2 answers:
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By definition, the average change of rate is given by:
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x