Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle = 
Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium = 
Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²
Answer:
The answer to your question is: midsegment = 35 units
Step-by-step explanation:
Use the Thales' theorem
43( 3x + 55) = 86( 6x + 5)
129x + 2365 = 516x + 430
129x - 516x = 430 - 2365
-387x = -1935
x = -1935 / -387
x = 5
Midpoint length = 6(5) + 5
= 30 + 5
= 35 units
You are basically looking to find the area of a circle
so to find the area of a circle the formula is A=pi R sqr
so if you take the radius which is half of the diameter 110 you get 55
you multiply 55*55 and get 3025
you than multiply that by pie and get
9503.32 if you round
Looks like (0,1) and (2,4) are on the line.
(0,1) is the y intercept, b=1
The slope is m=(4 - 1)/(2 - 0) = 3/2
Answer: y = (3/2) x + 1
Answer:
x = 8/3 and y = 32/3
Step-by-step explanation:
Add the two equations, getting -3y = -32, thus y = 32/3
Sub for y in first equation, getting 5x + 32/3 = 24
5x = 40/3
x = 8/3
