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Ierofanga [76]
3 years ago
10

Determine algebraically whether f(x)=3x-2 and g(x)=(x+2)/3 are inverse functions. Show all work.

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

f(x)=3 x-2      

     

y= 3 x-2      

             

x= 3y - 2  

     

3 y -2 = x

3 y -2 + 2 = x + 2

<u>3 y </u> =  <u>x  </u> +  <u>2</u>                                                      

3        3       3

<u>3 y </u> =  <u>x  </u> +  <u>2  </u>                                                    

3        3       3

y =  <u>x </u>  +  <u>2   </u>        replace y with f ^ -1(x)

   <em> </em>  3        3                                            

f ^-1 (x) =    <u>x</u>   +  <u>2 </u>        

                 3       3      

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Zielflug [23.3K]

Answers:  2700 and 5300 in that order

Katie invested <u>$2700</u> at a rate of 3% and <u>$5300</u> at a rate of 4%

===============================================================

Explanation:

  • x = amount invested at a rate of 3%
  • y = amount invested at a rate of 4%

Those two amounts must add to 8000 because this is how much she invests total. So x+y = 8000 is the first equation to set up.

The formula we'll be using is the simple interest formula, which is,

i = p*r*t

where p is the amount deposited or principal, r is the interest rate, and t is the number of years. Luckily, we don't have to worry about the time value t because t = 1 so it effectively goes away. We just need to worry about p and r.

The variable p will be tied directly to the values of x and y, as these are deposit amounts. The r values are decimal forms of the percentages (eg: 3% converts to 0.03)

In short, Katie will earn

  • 0.03x dollars from the first account (3% account)
  • 0.04y dollars from the second account (4% account)

In total, she earns 0.03x+0.04y dollars combined. This is set equal to 293 as this is the stated interest she earns over the entire year.

So another equation to set up is 0.03x+0.04y = 293

This only works for simple interest. Compound interest may likely be a different story.

----------------------------------------------------

To summarize so far, we found these two equations:

  • x+y = 8000
  • 0.03x+0.04y = 293

We have a number of options on how to solve this system. I'll use substitution.

Solve the first equation for y

x+y = 8000

y = 8000-x

Then we'll plug this into the other equation to solve for x like so,

0.03x+0.04y = 293

0.03x+0.04( y ) = 293

0.03x+0.04( 8000-x ) = 293

0.03x+0.04(8000)+0.04(-x) = 293

0.03x+320-0.04x = 293

-0.01x+320 = 293

-0.01x = 293-320

-0.01x = -27

x = -27/(-0.01)

x = 2700

This tells us that Katie invested $<u>2700</u> at 3%

Use this x value to find y

y = 8000-x

y = 8000-2700

y = 5300

She also invested $<u>5300</u> at 4%

----------------------------

As a quick check,

  • x+y = 2700+5300 = 8000

so that works out

Also,

  • 0.03*x = 0.03*2700 = 81
  • 0.04*y = 0.04*5300 = 212
  • 0.03x+0.04y = 81+212 = 293

which also works out. The answers are fully confirmed.

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