Answer:
The probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Step-by-step explanation:
Let <em>X</em> = number of household owns a sports car.
The probability of <em>X</em> is, P (X) = p = 0.07.
Then the random variable <em>X</em> follows a Binomial distribution with <em>n</em> = 3 and <em>p</em> = 0.07.
The probability function of a binomial distribution is:
![P(X=x) = {n\choose x}p^{x}[1-p]^{n-x}\\](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%7Bn%5Cchoose%20x%7Dp%5E%7Bx%7D%5B1-p%5D%5E%7Bn-x%7D%5C%5C)
Compute the probability that of the 3 households randomly selected at least 1 owns a sports car:

Thus, the probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Answer:
3x+2
Step-by-step explanation:
x+6/x+4+x-3/3
3x+6/4-3/3
3x+6/1/3
3x+6/3
3x+2
Answer: 20 weeks in 1 week
in 2 weeks 40
Step-by-step explanation:
This proves that the equation is true
In this item, we let x be the number of pairs of socks and y be the number of blouses that were purchased by Hanna. The total amount that is spent for the socks and blouses are 2.99x and 12.99y, respectively. The equation that would best describe the given scenario is,
2.99x + 12.99y = 43.92