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earnstyle [38]
3 years ago
10

What is the common ratio for the geometric sequence? 18, 12, 8, 16/3,…

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer:

2/3

Step-by-step explanation:

Given : A geometric sequence : 18, 12, 8, 16/3,…

Solution :

Each term is found by multiplying the previous term by a constant in a Geometric Sequence .

In a Geometric Sequence  common ratio is denoted by r


r = \frac{a_{n} }{a_{n-1} }


for n = 2


r = \frac{a_{2} }{a_{1} }


⇒r = \frac{12 }{18 }


⇒r = \frac{2 }{3 }


for n = 3


r = \frac{a_{3} }{a_{2} }


⇒r = \frac{8 }{12 }


⇒r = \frac{4 }{6 }


⇒r = \frac{2}{3 }


Thus the common ratio 'r' = 2/3

ivolga24 [154]3 years ago
6 0
Basically, what should we multiply each term by to get next term

18 times what=12
what=12/18=2/3

12 times what=8
what=8/12=2/3

common ratio is 2/3
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Artemon [7]
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LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
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L.A=2[1/2*4*6]+[6*8]+[8*7.211]
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The total are will be given by:
T.A=L.A+base area
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5 0
3 years ago
Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense
Fittoniya [83]

Answer:

3.33 and 1/3

Step-by-step explanation:

"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.

But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.

8 0
3 years ago
−7=s+(−13)<br> solve for S
skelet666 [1.2K]

Answer:6

Step-by-step explanation:

-7=s+(-13)

Open bracket

-7=s-13

Collect like terms

s=-7+13

s=6

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Tems11 [23]

Answer:

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Step-by-step explanation:

add variable to constant c+6

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ella [17]

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Step-by-step explanation: I worked it out.

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