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julsineya [31]
3 years ago
5

What is 83/30 as a mixed number?

Mathematics
2 answers:
DedPeter [7]3 years ago
8 0
83/30

1. How many times does 30 go into 83? 2 times.

30 * 2 = 60

So our integer is 2.

2. The remainder? 83 - 60 = 23

3. 2 23/30
Can't be simplified.

Answer: 2 23/30
Marat540 [252]3 years ago
5 0
A mixed number is a number with a fraction, like: 2 3/4ths for instance.

Take 83/30 and find what you have left:

30 goes into 83 two times, giving you 60. This leaves you with:

2 23/30 as an answer.

I hope this helps, have a great rest of your day! ^ ^
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In-s [12.5K]

Answer: 1590cm^3

Step-by-step explanation:

V=\frac{3\sqrt{3} }{2}a^2h

a = base

h = height

V=\frac{3\sqrt{3} }{2}(6cm)^2(17cm)

Solve the parentheses squared first.

V=\frac{3\sqrt{3} }{2}(36cm^2)(17cm)

2 and 36 can be simplied

2/2=1

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3 0
3 years ago
Please help!!!!! geometry
m_a_m_a [10]

Answer:

58

Step-by-step explanation:

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We are then told that side wx and yw are similar. This means that we have an isosceles triangle with two similar sides.

We are also told that angle w is equal to 64 degrees

with this information, we can assume that angle y is the same as angle x

Another important thing to note is that all triangle measures equals to 180

SO

we can make this expression:

64 + x + x = 180

Now to solve for x:

64 + x + x = 180

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3 0
11 months ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

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width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

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y = 21-x\\y = 21-11\\y = 10 inches

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7 0
3 years ago
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Brrunno [24]

Answer:

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4 0
3 years ago
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vovangra [49]

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Step-by-step explanation:

so it will be 3,0261

4 0
3 years ago
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