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Alex Ar [27]
3 years ago
7

Please help (click to veiw photo)

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
M - n 
m = 300x + 100, so we substitute that into the equation for m. 
300x + 100 - n 
n = 250x + 200, so we substitute that into the equation for n. 
300x + 100 - 250x - 200 
Subtract the 250x to get: 
50x + 100 - 200 
Subtract the 200 to get: 
50x - 100, which is option D. 
Hope this helps!
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What is 10.5% commission of $85,000
VikaD [51]
<span>What is 10.5% commission of $85,000

85,000 x 0.105 = 8,925

answer
$8,925 is </span>10.5% commission of $85,000
8 0
3 years ago
Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
4 years ago
Finding it hard. I’d love some help and the answers. Thanks
nevsk [136]

for all of them its base times height

v=bh

1) (8*6/2)*9.5=228

2) (4.5/2)^2 *8= 40.5

3) (3.3* 8.3/2) *5.4= 74.0

4) ((3.2+4.8)/2)* 2.7 *4.4= 47.5

7 0
2 years ago
H(-3), h(5), h(2), h(0)
romanna [79]

Answer:

h(-3) = -3h

h(5) = 5h

h(2) = 2h

h(0) = 0

5 0
3 years ago
From the given figure, find the value of x and y:<br>pls pls pls answer my question​
yKpoI14uk [10]

Answer:

have a great day

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6 0
3 years ago
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