Explanation:
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We can use the heat equation,
Q = mcΔT
where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Q = 11.2 kJ = 11200 J
m = <span>145 g
</span>c = ?
ΔT = (67 - 22) °C = 45 °C
By applying the formula,
11200 J = 145 g x c x 45 °C
c = 1.72 J g⁻¹ °C⁻¹
Hence, specific heat of benzene is 1.72 J g⁻¹ °C⁻¹.
Answer:
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Using ideal gas equation,
P\times V=n\times R\times T
Here,
P denotes pressure
V denotes volume
n denotes number of moles of gas
R denotes gas constant
T denotes temperature
The values at STP will be:
P=1 atm
T=273 K
R=0.0821 atm L mol ⁻¹
Mass of HCl given= 49.8 g
Molar mass of HCl given=36.41
Number of moles of gas, n= \frac{Given mass of the substance}{Molar mass of the substance}
Number of moles of gas, n= \frac{49.8}{36.46}
Number of moles of gas, n= 1.36
Putting all the values in the above equation,
V=\frac{1.36\times 0.0821\times 273}{1}
V=30.6 L
So the volume will be 30.6 L.
