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egoroff_w [7]
3 years ago
10

How would an increase in gradient affect the speed of water

Chemistry
1 answer:
stira [4]3 years ago
8 0
It will give the water more energy
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an apple pie needs 10 large apples, 2 crusts (top and bottom), one tablespoon of cinnamon. write a balanced equation that fits t
nasty-shy [4]
You're answer is 250 apples for 25 pies
4 0
3 years ago
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You have a 250. -ml sample of 1. 28 m acetic acid (ka = 1. 8 x´ 10–5). calculate the ph of the best buffer.
Nadya [2.5K]

The ph of the best buffer is 4.74

The given acetic acid is a weak acid

The equation of the pH of the buffer

pH = pKa + log ( conjugate base / weak acid ).

For best buffer the concentration of the weak acid and its conjugate base is equal.

pH = pKa + log 1

pH = pKa + 0

pH = pKa

given Ka = 1.8 × 10⁻⁵

pKa = - log ka

pH = -log ( 1.8 × 10⁻⁵ )

pH = 4. 74

Hence the pH of the best buffer is 4.74

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4 0
2 years ago
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How much force is needed to accelerate a 66 kg skier at 2 m/sec2
alexgriva [62]

Answer:

132N

Explanation:

F=ma

F=66×2

F=132N

7 0
3 years ago
Hellllpppp<br><br> What is propane's condensed structural formula?
mrs_skeptik [129]

<em>Answer,</em>

<u><em>Propane's condensed structural formula is CH3 CH2 CH3. </em></u>


<u><em>Hope This Helps :-)</em></u>

7 0
3 years ago
Calculate the number of chlorine atoms that are present in 66.05 g of dichloromethane, ch2cl2. when you have the number, take it
Whitepunk [10]
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of chlorine = 35.5 grams
Therefore,
molar mass of CH2Cl2 = 12 + 2(1) + 2(35.5) = 85 grams

number of moles = mass / molar mass
number of moles of CH2Cl2 = 66.05 / 85 = 0.777 moles

One mole of CH2Cl2 contains two moles of Cl and each chlorine mole has Avogadro's number of atoms in it.
Therefore,
number of chlorine atoms in 0.777 moles of CH2Cl2 can be calculated as follows:
number of atoms = 0.777 * 2 * 6.022 * 10^23 = 9.358 * 10^23 atoms

Now, we will take log base 10 for this number:
log (9.358 * 10^23) = 23.97119
5 0
3 years ago
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