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marta [7]
3 years ago
14

Perform the following

Chemistry
1 answer:
irinina [24]3 years ago
7 0

Answer:

12.0778

Explanation:

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The simplest formula is obtained by dividing the ______ of each element by the _______. 1. number of moles of each element; numb
alexandr402 [8]

Answer:

2. Number of moles ; smaller number of moles

Explanation:

The simplest formula also called the empirical formula is the ratio of moles to the number of smaller moles which is obtained by simply dividing the number moles with the number of smaller moles

7 0
3 years ago
Someone pls help me I will make you brain
Olegator [25]

Answer:

the second answer

Explanation:

5 0
3 years ago
Read 2 more answers
Estimate the solubility of m(oh)2 in a solution buffered at ph = 7.0, 10.0, and 14.0.
kherson [118]
<span>When M(OH)2 dissolves we have M(OH)2 which produces M2+ and 2OHâ’ pH + pOH=14 At ph =7; we have 7+pOH=14 pOH=14â’7 = 7 Then [OHâ’]=10^(â’pOH) [OH-] = 10^(-7) = 1* 10^(-7) At ph = 10. We have, pOH = 4. And [OH-] = 10^(-4) = 1 * 10^(-4) Finally ph = 14. We have, pOH = 0 And then [OH-] = 10^(-0) -----anything raised to zero power is 1, but (-0)... So [OH-] = 1</span>
4 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M Na_2CO_3

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol

6 0
3 years ago
Household bleach is an aqueous solution which has a pH of about 11 and feels slippery to the
Helen [10]
It’s b or d hope this helps
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3 years ago
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