The final temperature inside the container is 77.5°C
<h3>Solution ; </h3>
There are two heat transfers involved:
heat lost by bolt 1 + heat gained by bolt 2 = 0
-q(heat released by iron bolt) at higher temperature = q(heat gained by iron bolt) at lower temperature
-(cm)(T2-Treat higher temperature) = (cm)(T2-Tre at lower temperature)
-[0.450/(J/g-K) × m × (T2 -100°C)] = [0.450/(J/g-K) × m × (T2 -55°C)]
Or, -(T2 - 100°C) (T2 - 55°C) T2+T2 = 100°C + 55°C
Or, T2 = 155°C /2 = 77.5°C
<h3>What is Specific Heat ?</h3>
Specific heat is the amount of heat necessary to increase the temperature of one gram of a substance by one degree Celsius. Specific heat is often measured in calories or joules per gram per Celsius degree. Water, for example, has a specific heat of one calorie (or 4.186 joules) per gram per Celsius degree.
To know more about Specific Heat please click here : brainly.com/question/21406849
#SPJ4
The equation used for the calculation is P subscript 1 V subscript 1 equals P subscript 2 V subscript 2. Thus, option B is correct.
The pressure of the gas with respect to volume is given with inverse proportion. The ideal gas equation is given as:
<h3>Equation for relation between volume and pressure</h3>
The initial pressure of the gas has been given as, 
The initial volume of the gas has been, 
The final volume of the gas has been, 
The final pressure of the gas, 
is given as:
Thus, the equation used for the calculation is P subscript 1 V subscript 1 equals P subscript 2 V subscript 2. Thus, option B is correct.
Learn more about ideal gas, here:
brainly.com/question/8711877
Answer:
The volume of solution that contains 1.9 moles of NaOH is 3.42 L
Explanation:
To solve the question, we note that the solution contains 1.9 moles of 0.555 M NaOH
Therefore, 1000 mL contains 0.555 moles of NaOH
1000/0.555 mL contains 1 mole of NaOH
1.9 × 1000/0.555 mL contains 1.9 moles of NaOH
Therefore, the volume of solution that contains 1.9 moles of NaOH is 1.9 × 1000/0.555 mL or 3423.42342 mL = 3.42 L.
