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marta [7]
3 years ago
14

Perform the following

Chemistry
1 answer:
irinina [24]3 years ago
7 0

Answer:

12.0778

Explanation:

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The formula for a compound of Li₊ ions and Br_ ions is written LiBr. Why can't it be written Li₂Br? Why isn't it written BrLi?
bogdanovich [222]

Answer:

.

Explanation:

Lithium is in the first column of the periodic table, so it will have 1 valence electron.

Bromine is in the seventh column of the periodic table, so it will have seven valence electrons.

They must combine in a way to reach 8.

When combining elements to form compounds, the "crisscross method" is used. Above Li would be a charge of +1, and above Br would be a charge of -1.

Cross the 1 from the top of Li to the bottom of Br, and so there is 1 Br.

Cross the 1 from the top of Br to the bottom of Li, and so there is 1 Li.

It is not written BrLi because chemists decided to order them the other way. Technically speaking, it isn't wrong, but the positive charge is normally put on the left and the negative charge is normally put on the right.

5 0
3 years ago
Read 2 more answers
Which product is not made from a renewable resource? select one:
Lady bird [3.3K]
The answer is B plastic bags made from petroleum.
8 0
3 years ago
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WILL GIVE BRANLIEST TO WHOEVER ANSWERS THIS QUESTION>>> How many valence electrons does NaHCo3 have?
nydimaria [60]

Answer:

NaHCO3

Na = 1

H = 1

C = 4

Explanation:

5 0
3 years ago
Help me in my this plzzz ​
eduard

Answer:

a is oxidation

b is reduction

c is reduction

d is oxidation

hope it helps you

8 0
3 years ago
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When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ
Naddik [55]
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
        
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute: 
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025=  0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
 = 0.0075 * 63.546 =0.477 g


3 0
3 years ago
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