The chemical formula C₂H₆O, which is designated as option D, is equivalent to this structural formula.
<h3><u>What is a Chemical Formula ?</u></h3>
Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus (+) and minus () signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.
- An empirical formula represents by symbols, such as Na for sodium and Cl for chlorine, with subscripts that show the relative number of atoms in each.
- The composition of any member of an entire class of compounds can be represented by a general formula, a sort of empirical formula.
To know more about Chemical formulas, refer to:
brainly.com/question/26388921
Answer: The initial acceleration of the proton = (4.56 × 10^23) m/s2
The initial acceleration of the electron = (8.36 × 10^26) m/s2
Explanation: The force of attraction between the proton and electron can be computed using the statements of Coulomb's law which state that the force of attraction between two charged particles is directly proportional to the product of the two charges and inversely proportional to the square of their distances apart.
F = (Kq1q2)/(r^2) where K = (9 × (10^9) Nm(C^-2))
But q1 is the charge on a proton = (1.6 × (10^-19)) C
q2 is charge on an electron = -(1.6 × (10^-19)) C
r = (5.50 × (10^-10))mm = (5.50 × (10^-13))m
Computing all that, F = 0.0007616529 N = (7.62 × 10^-4) N
But the force of attraction is converted to that required for motion when they're released.
F = ma.
For proton, m = (1.67 × 10^-27) kg
a = F/m = 0.000762/(1.67 × 10^-27) = (4.56 × 10^23) m/s2
For electron, m = (9.11 × 10^-31) kg
a = F/m = 0.000762/(9.11 × 10^-31) = (8.36 × 10^26) m/s2
QED!
Answer:
1 mole represents 6.023×1023 particles.
1 mole of iodine atom= 6.023×1023
Given 127.0g of iodine.
no. of iodine atom = 1 mole of iodine
1mole of magnesium = 24g of Mg = 6.023×1023no.of Mg
Given 48g of Mg = 2×6.023×1023
no. of Mg = 2 moles of Mg
1 mole of chlorine atom= 6.023× 1023
no. of chlorine atom = 35.5g of chlorine atom
Given 71g of chlorine atom=2× 6.023× 1023
no. of chlorine atom = 6.023×1023
2 moles of chlorine atom.
Given that 4g of hydrogen atom.
will be equal to 4 × 6.023 × 1023
no. of atoms of hydrogen= 4 moles of hydrogen atom.
