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const2013 [10]
3 years ago
10

The student council is selling carnations for Valentine's Day. Two different shops can provide these flowers. . Gracie's Flowers

charges a $5.00 fee per order plus $0.75 per carnation Ben's Blooms charges a $10.00 fee per order plus $0.25 per carnation for an order. Gracie tells you the equation that would work with her shop: Using c to represent the total cost for an order of carnations and n to represent the number of carnations in the order, her equation is c=0.75n + 5.00 Ben is not sure how to write the equation for his shop. Fill in the following blanks to help him: C = nt​
Mathematics
1 answer:
natima [27]3 years ago
4 0

9514 1404 393

Answer:

  c = 0.25n +10.00

Step-by-step explanation:

The form of the equation is ...

  c = <cost per carnation>n + <fixed fee>

For Ben's shop, the equation would be ...

  c = 0.25n + 10.00

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If F(x) = 9x, which of the following is the inverse of F(x)?
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Should be x/9

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The length of a rectangle is (x+22. The width of the rectangle is (x^2+1). Which expression represents the perimeter of the rect
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Um I think its, To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

Step-by-step explanation:

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For circle H, JN = x, NK = 2, LN = 3, and NM = 6. Solve for x. circle H with chords JK and LM intersecting at N inside the circl
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x=9

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

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substitute the given values

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What is the simplest form of the expression 6x(x-4)-16x^2-(9x-1)?​
statuscvo [17]

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-10x^2-33x+1

Step-by-step explanation:

=>6x(x-4)-16x^2-(9x-1)

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= 6x^2-24x-16x^2-9x+1

arrange the like terms with same powers of x with the respective sign.

= 6x^2-16x^2-24x-9x+1

simplify by using the respective arthematic operations.

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8 0
3 years ago
We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

4 0
3 years ago
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