Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
__________________
-11x^2-5x-3
-(-11x^2-33x-33)
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28x+30
So our remainder will be 28x+30
Answer:
6x-7+32/4x+2
Step-by-step explanation:
Divide using polynomial division
It is just asking you to reorder the number so that the smallest number is first and the largest number is last.
The answer is: 8, 8.261, 8.4, 8.634
Answer:
Texting speed
Step-by-step explanation:
It's the dependent variable
