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xeze [42]
3 years ago
9

Which circle has a center angle that measures 40 degrees

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer: B

Step-by-step explanation:

A center angle is an angle that has rays that originate from the center.

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Let R be the region in the first quadrant of the​ xy-plane bounded by the hyperbolas xyequals​1, xyequals9​, and the lines yequa
Tema [17]

Answer:

The area can be written as

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = 0.2274

And the value of it is approximately 1.8117

Step-by-step explanation:

x = u/v

y = uv

Lets analyze the lines bordering R replacing x and y by their respective expressions with u and v.

  • x*y = u/v * uv = u², therefore, x*y = 1 when u² = 1. Also x*y = 9 if and only if u² = 9
  • x=y only if u/v = uv, And that only holds if u = 0 or 1/v = v, and 1/v = v if and only if v² = 1. Similarly y = 4x if and only if 4u/v = uv if and only if v² = 4

Therefore, u² should range between 1 and 9 and v² ranges between 1 and 4. This means that u is between 1 and 3 and v is between 1 and 2 (we are not taking negative values).

Lets compute the partial derivates of x and y over u and v

x_u = 1/v

x_v = u*ln(v)

y_u = v

y_v = u

Therefore, the Jacobian matrix is

\left[\begin{array}{ccc}\frac{1}{v}&u \, ln(v)\\v&u\end{array}\right]

and its determinant is u/v - uv * ln(v) = u * (1/v - v ln(v))

In order to compute the integral, we can find primitives for u and (1/v-v ln(v)) (which can be separated in 1/v and -vln(v) ). For u it is u²/2. For 1/v it is ln(v), and for -vln(v) , we can solve it by using integration by parts:

\int -v \, ln(v) \, dv = - (\frac{v^2 \, ln(v)}{2} - \int \frac{v^2}{2v} \, dv) = \frac{v^2}{4} - \frac{v^2 \, ln(v)}{2}

Therefore,

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = \int\limits_1^2 (\frac{1}{v} - v \, ln(v) ) (\frac{u^2}{2}\, |_{u=1}^{u=3}) \, dv= \\4* \int\limits_1^2 (\frac{1}{v} - v\,ln(v)) \, dv = 4*(ln(v) + \frac{v^2}{4} - \frac{v^2\,ln(v)}{2} \, |_{v=1}^{v=2}) = 0.2274

4 0
4 years ago
marissa wants to purchase song for hee ipod songs on itunes cost $1.25 each marisa found anothee webside called mp3 golore that
prisoha [69]
The equaton for cost is

first website is 1.25x
2nd is x+3

I'm assuming what number of songs wil make them have same cos
1.25x=x+3
minus x from both sides
0.25x=3
divide both sides by 0.25
x=12
answer is 12 songs must be purchased to spend the same on each website
8 0
3 years ago
from the graph below , determine the average rate at which the temperature changes per kilometer of altitude above the earth
Vedmedyk [2.9K]

Answer:

in order for me to help you with this  need this graph but i wish i could help you more on this with the picture

Step-by-step explanation:

6 0
3 years ago
A ball is thrown from an initial height of 7 feet with an initial upward velocity of 17ft/s . The ball's height h (in feet) afte
ra1l [238]
Hello,

-16t²+17t+7=11
==>16t²-17t+4=0
Δ=17²-4*4*16=33
==>t= (17-√33)/32=0.351732... (s)≈0.35 (s)
or t=(17+√33)/32=0.710767 (s)≈0.71 (s)
6 0
3 years ago
A ball is launched into the air from below a cliff, such that after t seconds its height above the cliff top is hmetres, and is
Verizon [17]

Answer:

7 meters

Step-by-step explanation:

In order to find the answer we need to calculate the first derivative of the function as follows:

h=-4.9*t^{2}+19.6*t-12.6\\h'=-4.9*2*t^{2-1}+19.6*1-0\\h'=-9.8*t+19.6

Now, for obtaining the time 't' when the ball reaches the maximum height:

h'=0\\-9.8*t+19.6=0\\t=19.6/9.8=2

Finally, we use the original equation for determining the height after 2 seconds:

h(2)=-4.9*2^{2}+19.6*2-12.6\\\\h(2)=7

In conclusion, the maximum height above the cliff top is 7 meters.

5 0
3 years ago
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