Answer:
if rounding by tenths 17.3 i’d rounding by hundredths 17.31 and thousandths 17.316
Step-by-step explanation:
most teachers say but off is thousandths be careful look what it’s asking for exactly
Answer:
Cluster sample
Step-by-step explanation:
This is an example of a cluster sample. In a cluster sample, the examiner divides the population into groups (each one of these groups is called a cluster) and once the examiner has these clusters, takes one of them and recollects the data from ALL the members of that cluster. In this case, the teacher divided the class in 3 different groups and then selects one of these groups and asks the average amount of time per week he/she spent studying.
It's 2.7 pounds because I set up a proportion of 150 over 90 = 4.5 over X and multiplied 90 * 4.5 divided by 150
Answer:
i think ur right or letter b butu not c
Step-by-step explanation:
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.




The test statistic can be written as :

which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 

= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.