Answer:
sss axiom
Step-by-step explanation:
<span>1. c, b
2. c, b
1.
To solve this problem, you really need to get a piece of graph paper and draw the triangles. For the triangle RST, you'll see that it's a right triangle with R being the right angle. The long leg of the triangle is close to the origin and the short leg is immediately below R. Then when you draw the triangle R'S'T', you'll see that it's still a right triangle. But now the long leg is parallel to the y axis and S' is now above R' instead of S being to right of R in the original triangle. So it looks like the triangle was rotated 90 degrees counter clockwise which is choice "c". So, draw a new triangle R"S"T" by rotating triangle RST 90 degrees counter clockwise. You'll see that point R" is at (1,-4), S" at (1,-1), and T" at (2,-4). All three of those points are located 2 units below the points R' S' T'. So you need to translate the triangle 2 units higher, which is choice b.
2. This is the exact same question with the exact same choices as #1 above. So the answer is exactly the same.</span>
Answer:
x = 0.343
Step-by-step explanation:
We want to solve:
5 - 3tan(3x) = 0
such that:
-π< x < π
where π = 3.14
then:
-3.14 < x < 3.14
Let's solve the equation:
5 - 3tan(3x) = 0
-3tan(3x) = -5
tan(3x) = -5/-3 = 5/3
Now we can use the inverse tan function, Atan(x).
Remember that:
Atan( tan(x) ) = tan( Atan(x)) = x
Then if we apply that function to both sides, we get:
Atan( tan(3x)) = Atan(5/3)
3x = Atan(5/3)
x = Atan(5/3)/3 = 0.343
Answer:
Yashoda got 1800
Step-by-step explanation:
Yashoda : Ingrid
3 : 2
Ingrid got 1200
Divide this by 2
1200/2 = 600
Multiply each side by 600
Yashoda : Ingrid
3*600 : 2*600
1800 : 1200
Yashoda got 1800
DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
