Question

One vegetable warehouse had 210 tons of potatoes, another one had 180 tons. 90 tons of potatoes were delivered to the first and 120 tons to the second warehouse every day. In how many days will the first warehouse have 1.2 times less potatoes than the second warehouse?

Answer 1

Answer:

The number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.

Step-by-step explanation:

Let

x: number of days

y: amount of potatoes

We can express the amount of potatoes in each warehouse using linear equations:

Warehouse #1: $y_1 = 90x+210$

Warehouse #2: $y_2 = 120x+180$

We need to find the value of x when $1.2*y_{1} =y_{2}$

Substituting the expressions for y1 and y2 in $1.2*y_{1} =y_{2}$:

$1.2*(90x+210) =120x+180$

Applying distributive law:

$108x+252 =120x+180$

Solving the equation by subtracting 108x and 180 on both sides:

$108x+252-108x-180 =120x+180-108x-180$

$252-180 =120x-108x$

$72 =12x$

Now we divide by 12 on both sides:

$\frac{72}{12} =\frac{12x}{12}\\6=x\\x=6$

Therefore, the number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.