Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- The coin is fair, hence p = 0.5.
- The coin is tossed 10 times, hence n = 10.
The probability that is lands tails up at least nine times is given by:
In which:
Hence:
0.0108 = 1.08% probability of the coin landing tails up at least nine times.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Answer:
5. -18x^3y^4 +54x^2y^4
6. 6x^2 -40x +50
Step-by-step explanation:
Use the distributive property. The factor outside parentheses multiplies each term inside parentheses.
__
<h3>5.</h3>
__
<h3>6.</h3>
One of them is 3,8,3,8 and the other is 4,6,4,6
Answer:
If it is less than 3, Player 1 earns 3 points.
If not, Player 2 earns 2 points.
Step-by-step explanation:
<u>Player 1</u> :
p(N < 3) = p(N = 1 or N = 2) = 2/5
<u>Player 2</u> :
p(N ≥ 3) = p(N = 3 or N = 4 or N = 5) = 3/5
<u>We notice that</u> :
p(N < 3) × 3 = (2/5) × 3 = 6/5
On the other hand,
p(N ≥ 3) × 2 = (3/5) × 2 = 6/5
since ,the probability player 1 win multiplied by the associated number of points (3)
is equal to
the probability player 2 win multiplied by the associated number of points (2).
Then the game is fair.
