Percent change = ((new value) - (old value))/(old value) × 100%
= (180 -135)/135 × 100%
= 33 1/3%
180 is about 33% greater than 135.
Answer:
The probability of selecting a black card or a 6 = 7/13
Step-by-step explanation:
In this question we have given two events. When two events can not occur at the same time,it is known as mutually exclusive event.
According to the question we need to find out the probability of black card or 6. So we can write it as:
P(black card or 6):
The probability of selecting a black card = 26/52
The probability of selecting a 6 = 4/52
And the probability of selecting both = 2/52.
So we will apply the formula of compound probability:
P(black card or 6)=P(black card)+P(6)-P(black card and 6)
Now substitute the values:
P(black card or 6)= 26/52+4/52-2/52
P(black card or 6)=26+4-2/52
P(black card or 6)=30-2/52
P(black card or 6)=28/52
P(black card or 6)=7/13.
Hence the probability of selecting a black card or a 6 = 7/13 ....
C= chair cost
t= table cost
Create two equations with the given information. Solve for one variable in equation one. Substitute that answer in equation two. Then you can solve for the needed information.
3c+2t=$18
5c+6t=$48
3c+2t=18
Subtract 2c from both sides
3c=18-2t
Divide both sides by 3
c=(18-2t)/3
Substitute the value for c in equation two:
5c+6t=$48
5((18-2t)/3)+6t=48
(90-10t)/3+6t=48
Multiply everything by 3 to eliminate fraction
(3)((90-10t)/3)+(3)(6t)=(3)(48)
90-10t+18t=144
90+8t=144
Subtract 90 from both sides
8t=54
Divide both sides by 8
t=$6.75 cost for table
Substitute the t value to solve for c:
3c+2t=18
3c+2(6.75)=18
3c+13.50=18
3c=4.50
c=$1.50 chair cost
Check:
5c+6t=$48
5(1.50)+6(6.75)=48
7.50+40.50=48
48=48
Hope this helps! :) If it does, please mark as brainliest.
Answer:
a=2
Step-by-step explanation:
u=3b-2(2) or u=3b-4
An acite becaues it lowers than the others