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likoan [24]
3 years ago
10

A line passes through (2, −1) and (4, 5).

Mathematics
2 answers:
liberstina [14]3 years ago
7 0
The answer to the first question is B
The second question is B
PSYCHO15rus [73]3 years ago
6 0

Answer:

<h2>1) Option B is the correct answer.</h2><h2>2) Option B is the correct answer.</h2>

Step-by-step explanation:

1) We have equation of line passing through (x₁,y₁) and (x₂,y₂) given by

                       y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

   (x₁,y₁) = (2, −1) and (x₂,y₂) = (4, 5)

Substituting

       y-(-1)=\frac{5-(-1)}{4-2}(x-2)\\\\y+1=3(x-2)\\\\y+1=3x-6\\\\-3x+y=-7

Option B is the correct answer.

2) Point slope form of line is given by

                 y-y₁ = m(x-x₁)

        (x₁,y₁) = (1, 9) and m = 5

     Substituting    

               y-9 = 5(x-1)        

     Option B is the correct answer.  

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Ben had two copies of the same poster in different sizes. Both posters are in the shape of a square. The side length of the two
omeli [17]

Answer:

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

the question states that a person named Ben has two copies of the same poster having different sizes , provided they both are squares !

further , we've been given that the side length of the posters are in the ratio of 3:7 and the perimeter of the smaller posted is 27 cm .

We've been asked to find the perimeter of the bigger poster !

so let's start ~

let\: the \: length \: of \: the \: smaller \: poster \: be \: 3x \\  \\ let \: the \: length \: of \: the \: bigger \: poster \: be \: 7x \\  \\ now \: , \:  \\  \\ perimeter \: of \: square = 4 \times side \\  \\ \implies \: perimeter \: of \: shorter \: square = 4 \times 3x \\  \\ \implies \: 27 = 3x \\  \\ x =  \cancel\frac{27}{3}  \\  \\ \implies\red{\boxed{ \: x = 9 \: cm}}

now ,

side \: length \: of \: bigger \: square = 7x \\  \\ \implies \: 7 \times 9 = 63 \: cm \\  \\ \therefore \: perimeter \: of \: bigger \: square = 4 \times 63 \\  \\ \bold\pink{\implies \: 252 \: cm}

hope helpful :D

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2 years ago
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