If you call 
the mass of the ant and 
the load, we have the equation
In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.
Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:
Kate will travel 8 feet backwards
The answer would be -2 i had the same problem on my quiz and the correct answer was -2
Answer:. This would be 0.81^20 for none of the 19=0.0148
Step-by-step explanation:With a tree diagram, there are two possibilities, one is ND from 1 D from 2, with probability (5/8)(2/5)=(1/4) and the other is (3/8)(3/5)=9/40 That would be 19/40 for the answer.
3. Poisson parameter lambda=5
for P(0), it is e^(-5)(5^0)/0! or e^(-5)=0.0067
for P(1), it is e^(-5)(5^1)/1! or 5e(-5)
The total probability is 6e^-5 or 0.0404
4. the mean is 1000 hours, so lambda is the reciprocal or 1/1000
the probability it will last <800 hours is 1-e^(-800*1/1000) or 1-e^(-.8)=0.5507
5. assume p=0.4 since it ca't be 4
sd is sqrt (np*(1-p))=sqrt (6*0.6=sqrt(3.6)=1.90
Answer:
Step-by-step explanation:
