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Olin [163]
3 years ago
10

suppose 1 gold bar is 6 cm long, 2 cm high, and 3 cm wide. how many whole gold bars will you be able to fit in a vault with a vo

lume of 500 cm3?
Physics
1 answer:
Gemiola [76]3 years ago
5 0
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
                              v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values, 
                            v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
                                      n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.

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A plant dying after being exposed to poison represents a physical change.
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Answer:

False is the correct answer.

It is considered more of a chemical change because all of the cells inside the plant decompose (change chemicaly)

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give an example of one living and one non-living thing that uses the force of buoyancy to function. explain how they work.
zaharov [31]

Answer:

the biotic one is a human in water and they flaot because of the air in our lungs and the abiotic one is a swimming buoys are filled with foam and foam floats

Explanation:

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2 years ago
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Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will
djyliett [7]

Answer:

The resulting pressure is 3 times the initial pressure.

Explanation:

The equation of state for ideal gases is described below:

P\cdot V = n \cdot R_{u}\cdot T (1)

Where:

P - Pressure.

V - Volume.

n - Molar quantity, in moles.

R_{u} - Ideal gas constant.

T - Temperature.

Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:

P_{1}\cdot V_{1} = P_{2}\cdot V_{2} (2)

If we know that \frac{V_{2}}{V_{1}} = \frac{1}{3}, then the resulting pressure of the system is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)

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The resulting pressure is 3 times the initial pressure.

4 0
3 years ago
An old light bulb draws only 54.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what facto
Lemur [1.5K]

Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

R\propto\dfrac{1}{D}

The power is inversely proportional to the resistance.

P\propto\dfrac{1}{R}

P\propto D^2

We need to calculate the factor of the diameter of the filament reduced

Using relation of power and diameter

\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}

Put the value into the formula

\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}

\dfrac{D_{i}}{D_{f}}=0.95

D_{i}=0.95 D_{f}

Hence, The factor of the diameter is 0.95.

7 0
3 years ago
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If you can answer all of this then your a legend (I'm giving you all my points)
navik [9.2K]

Answer:

1. B

2. B

3. D

4. A

Hope this was correct! A lot of the answers are already in the article itself and the wording is just different. I suggest now that for information retainment, you read the article again with the correct points in mind and see if you can spot the points where the answers are stated!

3 0
3 years ago
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