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Lera25 [3.4K]
4 years ago
12

What happens to light waves from a star as the star moves toward Earth?

Physics
2 answers:
Ksivusya [100]4 years ago
4 0

Answer:

The other person is right, the answer is they appear to shift towards blue.

Explanation:

Musya8 [376]4 years ago
3 0
This shifts the star’s spectral lines toward the blue end of the spectrum. If the star is moving away from us, it’s waves are effectively stretched out when they reach earth, increasing their wavelength. This shifts the star’s spectral lines toward the red end of the spectrum.
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Two objects have the same size and shape, but one is much heavier than the other. When they are dropped simultaneously from a to
maria [59]

Answer:

None of the above.

The correct answer would be momentum

6 0
3 years ago
The boiling point of a substance is _72 degree Celsius. This temperature will be equivalent to Kelvin scale is-------.
Vlada [557]

Answer:

345 K

Explanation:

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object.

Generally, it is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).

<u>Given the following data;</u>

  • Boiling point = 72°C

<em>To convert the temperature in degree Celsius to Kelvin, we would use the following mathematical expression;</em>

Kelvin = 273 + °C

Substituting into the formula, we have;

Kelvin = 273 + 72

<em>Kelvin = 345 K</em>

<em>Therefore, the temperature of 72°C will be equivalent to 345 K on the Kelvin scale.</em>

3 0
3 years ago
Learning Goal: To review the concept of conservative forces and to understand that electrostatic forces are, in fact, conservati
CaHeK987 [17]

Explanation:

The electrostatic forces are conservative forces!

The mainly property of the conservative fields is \vec{\nabla} \times \vec E=\vec 0

In spherical coordinates the field's expression is:

\vec E=\frac{Q}{4\pi \epsilon _0 r^2} .\^r

and the curl expression is:

\nabla\times \vec E=\frac{1}{r^2{\sin}\,\theta}\left|\begin{matrix}\hat{r} & r\,\hat{\theta} & r\,{\sin}\,\theta\,\hat{\varphi}  \\& & \\\frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \varphi}\\ & & \\E_r & rE_\theta & r{\sin}\,\theta\, E_\varphi\end{matrix}\right|=(0, 0, 0)

to find the expression for the potential function associated:

\vec E=\vec \nabla . V, \Delta V= V_b-V_a=-\int _c \vec E.d\vec l=-\int _c E\^r.dr\^r=-\int _c Edr=\int \limits^a_b \frac{Q}{4\pi \epsilon _0 r^2} dr= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{r}|^b_a)= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{b}-\frac{1}{a})

5 0
3 years ago
The natural resistance of any object to change its speed is called _____.
Stella [2.4K]
This natural resistance is known as inertia. =)
6 0
3 years ago
Owen is going on a multi-day hike up a large mountain. He wants to know what clothes he should bring for the higher elevation as
faltersainse [42]
The answer is c hope this helps
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3 years ago
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