Here is a list of numbers: 20, 13, 1, 13, 6, 1,8,20,9,18 State the median.
1 answer:
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Answer:
for a a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}
for b
b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}
for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}
for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}
Step-by-step explanation:
in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix
for a a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}
for b
b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}
for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}
for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}
Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).