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Lesechka [4]
3 years ago
8

Solve for x in the equation x^2-8x+41=0

Mathematics
2 answers:
Dovator [93]3 years ago
8 0
X = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 4 +or- 5i

marshall27 [118]3 years ago
3 0
See photo for the solution and answer.

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I have the simplified Answer I just need the excluded value
andreev551 [17]
Excluded value: x = 6
7 0
3 years ago
6 + (8 ÷ 2) - 2 + (4 - 1)
den301095 [7]

Answer:

11

Step-by-step explanation:

6 + (8 ÷ 2) - 2 + (4 - 1) =  

6 + 4 - 2 + 3 =

11

have a nice day! :)

7 0
3 years ago
The intersection of lines y=-14x+3 and y=-32x+3 is .
Kamila [148]

The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

<h3>How to determine the intersection of the lines?</h3>

The lines are given as:

y = -14x + 3 and y = -32x+3

Substitute y = -32x+3 in

-32x+3 = -14x + 3

Evaluate the like terms

-18x = 0

Divide by -18

x = 0

Substitute x = 0 in y = -14x + 3

y = -14(0) + 3

Evaluate

y = 3

Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

Read more about linear equations at:

brainly.com/question/14323743

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6 0
2 years ago
When 9/10 is divided by 2/5 , will the quotient be greater than 1 or less than 1.
Feliz [49]
9/10 * 5/2 = 45/20
The quotient will be greater than 1
3 0
3 years ago
Read 2 more answers
A
KATRIN_1 [288]

Answer:

D. Zacpszcap. is probably the answer

7 0
2 years ago
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