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3 years ago

Determine the intercepts of the line that passes through the following points.

Mathematics

1 answer:

Katen [24]3 years ago

5 0

remember, x is on the left side for x- intercept while Y is on the right but you put it on the left for the Y intercept.

example

x intercept is (-5, 0, 5)

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The formula for the volume of a cone is V = jarh, where V is the volume, r is the radius, and h Is the heightWhat is the volume

olga nikolaevna [1]

Given:

The radius, r=4x

The height,

$h=21xy^2$

To find the volume of the cone:

The volume of the cone formula is,

$V=\frac{1}{3}\pi r^2h$

Substitute the values of r and h in the above formula we get,

$\begin{gathered} V=\frac{1}{3}\pi\times(4x)^2\times21xy^2 \\ =\frac{1}{3}\pi\times16x^2\times21xy^2 \\ =\pi\times16x^2\times7xy^2 \\ =112\pi x^3y^2 \end{gathered}$

Hence, the volume of the cone is

$V=112\pi x^3y^2$

Thus, the correct option is option D.

7 0

6 months ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters are given as follows:

$\overline{x} = 111000, \sigma = 36730, n = 36$

Hence, the lower bound of the interval is:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002$

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0

1 year ago

Express in exponential form log(2)16 = 4

S_A_V [24]

$\bf \textit{exponential form of a logarithm}
\\\\
log_a b=y \implies a^y= b\qquad\qquad 
% exponential notation 2nd form
a^y= b\implies log_a b=y \\\\
-------------------------------\\\\
log_2(16)=4\qquad \qquad \implies \qquad 2^4=16$