what are the possible numbers of positive real, negative real and complex zeros of f(x)=4x^3+x^2+10x-14
1 answer:
Answer:
Positive real 1
Negative real 0
Complex 2
Step-by-step explanation:
∵ 4x³ + x² + 10x - 14 = 0 is third degree
∴ It has three roots:
1 positive real root
2 conjugate complex roots
You might be interested in
X^2 + 7x + 10
Find the factors of 10 that add up to 10.
1* 10, 2*5
The factors are 2*5
(x+2)(x+5)
Answer:
sorry
Step-by-step explanation:
Answer:
86
Step-by-step explanation:
Difference means subtraction so you do 136-50 :)
It's hard to explain, but theres a trick to it too.