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blondinia [14]
3 years ago
14

Which value is a solution to the inequality x – 4 > 15.5?

Mathematics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

x>19.5

Step-by-step explanation:

Let's solve your inequality step-by-step.

x−4>15.5

Step 1: Add 4 to both sides.

x−4+4>15.5+4

x>19.5

Answer:

x>19.5

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What is the predicted profit when the number of items made (x) is 2,500, and the number of stores stocking the product (x2) is 5
ElenaW [278]

Answer:

d. 75,595

Step-by-step explanation:

Given the estimated regression equation :

y=550 + 30x1 + 9x2

if number of items made (x) = 2500 ; number of stores stocking the product (x2) = 5

Predicted profit (y) will be :

Substitute the values x1 = 2500 and x2 = 5 into the estimated regression model:

y=550 + 30(2500) + 9(5)

y = 550 + 75000 + 45

y = 75595

Hence, the predicted profit will be 75,595

5 0
3 years ago
Can anyone help me with this problem. This question is a little hard. Is anyone on to help. Can’t understand
exis [7]

Answer: It should be D if im looking at this correctly

Step-by-step explanation:

Plain and simple

7 0
1 year ago
Read 2 more answers
Factorise x cubed - x
kirill [66]

Answer:

= x(x+1)(x-1)

Step-by-step explanation:

Given the expression x³ - x

On factorizing

x³ - x

= x(x²-1)

Using difference of two square

a² - b² = (a+b) (a-b)

x² - 1

= x² - 1²

= (x+1)(x-1)

The complete factor

x³ - x

= x(x²-1)

= x(x+1)(x-1)

7 0
3 years ago
Help please this is due today
dangina [55]

The experimental probability that in a group of 4 students, at least one of them has brown eyes is 95%.

<h3>What is Experimental Probability?</h3>

Experimental probability is a probability that is determined on the basis of a series of experiments. A random experiment is done and is repeated many times to determine their likelihood and each repetition is known as a trial. The experiment is conducted to find the chance of an event to occur or not to occur.

Here , Favorable Outcome = 19

          Total outcomes = 20

Probability = Favorable Outcome/ Total Outcome

                   = 19 / 20

                   = 95%

Thus, the experimental probability that in a group of 4 students, at least one of them has brown eyes is 95%.

Learn more about Experimental Probability from:

brainly.com/question/15729871

#SPJ1

5 0
2 years ago
Ronald scores 700 on the math section of the SAT exam. The distribution of SAT scores is approximately normal with a mean of 500
Artist 52 [7]

Answer:

a) Due to the higher z-score, Ronald performed better relative to his peers on the test.

b) Ronald needed a grade of at least 732.5, and Rubin of at least 33.58.

c) 95% of the population fall between graded of 4.868 and 31.132 on the ACT.

95% of the population fall between graded of 304 and 696 on the SAT.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

(a) Relative to their peers who also took the tests, who performed better on his test? Explain.

We have to find whoever has the higher z-score.

Ronald:

Ronald scores 700 on the math section of the SAT exam. The distribution of SAT scores is approximately normal with a mean of 500 and a standard deviation of 100. So the z-score is found when X = 700, \mu = 500, \sigma = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{700 - 500}{100}

Z = 2

Rubin:

Rubin takes the ACT math exam and scores 31 on the math portion. ACT scores are approximately normally distributed with a mean of 18 and a standard deviation of 6.7. So the z-score is found when X = 31, \mu = 18, \sigma = 6.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{31 - 18}{6.7}

Z = 1.94

Due to the higher z-score, Ronald performed better relative to his peers on the test.

(b) A certain school will only consider those students who score in the top 1% in the math section. What grades would Ronald and Rubin have to receive on their respective tests to be considered for admission?

They have to be in the 100 - 1 = 99th percentile, that is, they need a z-score with a pvalue of at least 0.99. So we need to find for them X when Z = 2.325.

Ronald:

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 500}{100}

X - 500 = 232.5

X = 732.5

Rubin:

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 18}{6.7}

X - 18 = 15.58

X = 33.58

Ronald needed a grade of at least 732.5, and Rubin of at least 33.58.

(c) Between what two grades does 95% of the population fall for the ACT and the SAT exams?

They fall between the 100 - (95/2) = 2.5th percentile and the 100 + (95/2) = 97.5th percentile, that is, they fall between X when Z = -1.96 and X when Z = 1.96.

ACT:

Lower bound:

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 18}{6.7}

X - 18 = -1.96*6.7

X = 4.868

Upper bound:

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 18}{6.7}

X - 18 = 1.96*6.7

X = 31.132

95% of the population fall between graded of 4.868 and 31.132 on the ACT.

SAT:

Lower bound:

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 500}{100}

X - 500 = -196

X = 304

Upper bound:

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 500}{100}

X - 500 = 196

X = 696

95% of the population fall between graded of 304 and 696 on the SAT.

7 0
3 years ago
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