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Sveta_85 [38]
3 years ago
7

if a school starts at 11:00 and the kids who take the bus have to get to the bus stop 3 hours and 20 minute from there regular b

us time which is 7:05 what time should they get to the bus stop?
Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0
The time they need to be there should be 10:25
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Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).
lesya [120]

Answer:

-7x + 4y = +42

Step-by-step explanation:

Going from point (2, -7) to point (6, 0), x increases by 4 and y increases by 7.  Thus, the slope of the line in question is m = 7/4.

Starting from the equation y = mx + b, and subbing (7/4) for m, 6 for x and 0 for y, we get:

0 = (7/4)(6) + b.  Then b = 42/4, or 21/2.  Thus, we now have y = (7/4)x + 21/2.

We must put this into "standard form."  Multiplying all three terms by 4, we get:

4y = 7x + 42.  Rearranging these terms to fit the "standard form" equation Ax + By = C, we get:

-7x + 4y = +42

5 0
3 years ago
There is strong believe that language skills of Political science students are greater than students who study Finance. Research
BaLLatris [955]

Answer:

a

The null hypothesis is  H_o :  \mu_1 = \mu_2

The alternative hypothesis  H_a : \mu_1 >  \mu_2

b

p-value   = 0.232

c

    The decision rule is  

Fail to reject the null hypothesis

Step-by-step explanation:

From the question we are told that

  The value given is  

S/N

1       7 5

2      4 3

3      8 7

4      8 8

5      7 9

6      7 5

7      6 5

Generally the sample mean for the first sample  is  mathematically represented as

        \= x _1 = \frac{\sum x_i }{n}

=>     \= x _1 = \frac{7 +4 + \cdots + 6}{7}

=>     \= x _1 =  6.714

Generally the sample mean for the second sample is mathematically represented as

        \= x _2 = \frac{\sum x_i }{n}

=>     \= x _2 = \frac{5 + 3+ \cdots + 5}{7}

=>     \= x _2 =  6

Generally the sample standard deviation  for the first sample  is  mathematically represented as

           s_1 = \sqrt{\frac{\sum (x_i - \= x_1)^2 }{n-1 } }

=>       s_1 = \sqrt{\frac{ (7 - 6.714 )^2 +(4 - 6.714 )^2 + \cdots + (6 - 6.714 )^2 }{7-1 } }

=>       s_1 = 1.905

Generally the sample standard deviation  for the second  sample  is  mathematically represented as

           s_2 = \sqrt{\frac{\sum (x_i - \= x_2)^2 }{n-1 } }

=>       s_2 = \sqrt{\frac{ (5 - 6.714 )^2 +(3 - 6.714 )^2 + \cdots + (5 - 6.714 )^2 }{7-1 } }

=>       s_1 = 4.33

Generally the pooled standard deviation is  

      s = \sqrt{\frac{(n_1 - 1 )s_1^2 + (n_2 - 1 )s_2^2}{n_1 + n_2 -2 } }

=>    s = \sqrt{\frac{(7 - 1 )1.905^2 + (7 - 1 )4.333^2}{7 + 7 -2 } }

=>    s = 1.766

The null hypothesis is  H_o :  \mu_1 = \mu_2

The alternative hypothesis  H_a : \mu_1 >  \mu_2

Generally the test statistics is mathematically represented as

      t = \frac{\= x _1 - \= x_2 }{s * \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}  }

=>   t = \frac{6.714  - 6 }{1.766  * \sqrt{\frac{1}{7} + \frac{1}{7}}  }

=>   t = 0.757

Generally the degree of freedom is mathematically represented as

     df = n_1 + n_2 - 2

=>   df = 7 + 7 - 2

=>   df = 12

From the t distribution table the probability of  t = 0.757 at a degree of freedom of df = 12 is  

     t_{ 0.757 , 12} = 0.232

Generally the p-value is  

      p-value  = t_{ 0.757 , 12} = 0.232

From the values  obtained we see that p-value >  \alpha  hence  

   The decision rule is  

Fail to reject the null hypothesis

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What is the solution to the inequality?<br><br> 4(2x+5)-2x more than or equal to 10
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See attached for the solution

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